2/x-5+x/x^2-25=4/x+5

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Solution for 2/x-5+x/x^2-25=4/x+5 equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

2/x+x/(x^2)-25-5 = 4/x+5 // - 4/x+5

2/x+x/(x^2)-(4/x)-25-5-5 = 0

2/x+x/(x^2)-4*x^-1-25-5-5 = 0

-1*x^-1 = 35 // : -1

x^-1 = -35

-1 < 0

1/(x^1) = -35 // * x^1

1 = -35*x^1 // : -35

-1/35 = x^1

x = -1/35

x = -1/35

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